3x^2+25x=50

Solution for 3x^2+25x=50 equation:

3x^2+25x=50

We move all terms to the left:

3x^2+25x-(50)=0

a = 3; b = 25; c = -50;
Δ = b2-4ac
Δ = 252-4·3·(-50)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-35}{2*3}=\frac{-60}{6}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+35}{2*3}=\frac{10}{6}
=1+2/3
$